It’s getting pretty expensive to fly these days — not because of ticket prices, but because of the ridiculous number of bags you need to buy!

Consider again your shiny gold bag and the rules from the above example:

• faded blue bags contain 0 other bags.
• dotted black bags contain 0 other bags.
• vibrant plum bags contain 11 other bags: 5 faded blue bags and 6 dotted black bags.
• dark olive bags contain 7 other bags: 3 faded blue bags and 4 dotted black bags.

So, a single shiny gold bag must contain 1 dark olive bag (and the 7 bags within it) plus 2 vibrant plum bags (and the 11 bags within each of those): 1 + 1*7 + 2 + 2*11 = 32 bags!

Of course, the actual rules have a small chance of going several levels deeper than this example; be sure to count all of the bags, even if the nesting becomes topologically impractical!

Here’s another example:

shiny gold bags contain 2 dark red bags.
dark red bags contain 2 dark orange bags.
dark orange bags contain 2 dark yellow bags.
dark yellow bags contain 2 dark green bags.
dark green bags contain 2 dark blue bags.
dark blue bags contain 2 dark violet bags.
dark violet bags contain no other bags.

In this example, a single shiny gold bag must contain 126 other bags.

Assignment

How many individual bags are required inside your single shiny gold bag? Determine this in the following way:

• Write a function shinyGoldSize that takes the pathname (String) of a text file containing a list of rules, one rule per line. The function must return how many (Number) individual bags are required inside your single shiny gold bag.

Example

In this interactive session we assume the text files rules1.txt¹ and rules2.txt² to be located in the current directory.

> shinyGoldSize("rules1.txt")
32
> shinyGoldSize("rules2.txt")
126