There has been a gathering of more than one Martian somewhere in a cave on Mars. These Martians do not really have hands, but they do have some finger-like extensions that are directly attached to their bodies. All Martians have the same number of fingers, and that number is at least two. Altogether there are between 200 and 300 Martian fingers in the cave (including the lower and upper limits). If you knew the exact number fingers in the cave, you could deduce the exact number of Martians. How many Martians are there, and how many fingers does each one have?


The key to the solution of this problem is that the number of fingers can tell us uniquely the number of Martians. That's a tall order. It eliminates, say, 246 fingers because that's too ambiguous: there might be 82 Martians with 3 fingers each or 3 Martians with 82 fingers each, and so on.

The only possibility that avoids this uncertainty is that the quantity of Martians and the quantity of fingers per Martian are expressed by the same number, and that this number is not composite. That means we're looking for the square of a prime number, and the only such number in the range 200–300 is 289 (or $$17^2$$). So there are 17 Martians, each of which has 17 fingers.


The input contains two integers $$m, n \in \mathbb{N}$$ such that $$m \leq n$$. It is guaranteed that there's only a single prime number $$p$$ such that $$m \leq p^2 \leq n$$.


The output must contain the text There are $$p$$ Martians having $$p$$ fingers each., where $$p$$ must be filled up by the only prime number that meets the condition $$m \leq p^2 \leq n$$.





There are 17 Martians having 17 fingers each.