Is it a leap year?
★☆☆In 1582 the Gregorian calendar was introduced. Our planet takes approximately 365.25 days to orbit the sun once. It's that .25 that creates the need for a leap year every four years. During non-leap years (common years) the calendar doesn't take into account the extra quarter of a day required by Earth to complete a single orbit. In leap years there are 29 days in February instead of 28.
Write a program to say whether the year entered by a user is a leap year or not. Any year exactly divisible by four is usually a leap year unless it is also divisible by one hundred. The exception is that all years divisible by four hundred are always leap years.
Remember to add a comment before a subprogram, selection or iteration statement to explain its purpose.
is_leap_year that:Enter a year: 1900
1900 is not a leap year.
Enter a year: 2000
2000 is a leap year.
Enter a year: 2022
2022 is not a leap year.
Enter a year: 2024
2024 is a leap year.
# Leap year program
# -------------------------
# Subprograms
# -------------------------
# Function to return if a year is a leap year
def is_leap_year(year):
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leap_year = False
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# If the year is divisible by 4 it is a leap year...
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if year % 4 == 0:
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leap_year = True
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# ...however, if it is also divisible by 100 it is not a leap year
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if year % 100 == 0:
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# ...but if it is divisible by 400 then it is a leap year
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if year % 400 == 0:
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leap_year = True
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# All other years are not leap years
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else:
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leap_year = False
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else:
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leap_year = True
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else:
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leap_year = False
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return leap_year
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# -------------------------
# Main program
# -------------------------
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year = int(input("Enter a year: "))
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if is_leap_year(year):
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print(year, "is a leap year.")
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else:
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print(year, "is not a leap year.")